Finally, we find the derivative of the function. To do that, we multiply each quantity variable by that variable's exponent and then reduce the exponent by one. For the equation above, that looks like this:
($20 * 1 x q^(1-1)) - (2 x q^(2-1) / 10) = ($20 x q^0) - (2 x q^1 / 10)
$20 * q becomes $20 x q^0, and any number raised to the power of 0 equals 1, so that component is simply $20. The q^2 / 10 component becomes 2 x q^1 / 10, or q / 5. Put it together, and the marginal revenue derivative is $20 - (q / 5). So, if you make 50 units of a product, the marginal revenue derivative will be $20 - 50 / 5, or $10.
Keeping it simple
Of course, you can simply do things by hand to get a sense of marginal revenue from a change in quantity. For instance, using the demand function above, the total revenue for the production of 50 units would be $750. Increase production to 60 units, and the price would fall to $14, but revenue would rise to $840.
The difference is $90, or $9 per unit. That doesn't exactly match the $10 figure above because the marginal revenue derivative calculation only applies directly at the 50-unit mark of production and diverges as you move away from that point.
Even with its limitations, the marginal revenue derivative can be helpful in making production decisions. By knowing how much additional production will affect sales, you can be smarter about choosing the right amount to provide to your customers.
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